Rate of Salmonella among U.S. adults by state 2017

Salmonella rate in the United States as of 2017, by state (new cases per 100,000 population)

The data describes the rate of Salmonella in the U.S., as of 2017, by state. As of that year, Idaho had the second highest rate of Salmonella in the U.S. with almost 36 new cases per every 100,000 population.

Salmonella in the U.S. Within the U.S., the rate of salmonella was the second highest in Idaho, totaling about 35.6 new cases per 100,000 population, as of 2017, only topped by Mississippi with 35.7 new cases per 100,000 population. In total, there were 17.2 cases of salmonellosis per every 100,000 population in the U.

Maine 9.3
Nevada 9.6
Michigan 9.7
Indiana 10.1
Alaska 10.6
West Virginia 10.8
Colorado 11.3
New York 11.3
Ohio 11.7
Connecticut 12.1
Kentucky 12.1
Vermont 12.1
Pennsylvania 12.4
New Jersey 12.8
New Hampshire 13
Oregon 13.1
Tennessee 13.6
Rhode Island 13.6
Virginia 14.1
California 14.3
Illinois 14.3
Washington 14.5
Utah 15.4
Maryland 16
Missouri 16.2
Nebraska 16.3
Delaware 16.8
Wyoming 16.9
Arizona 17
Wisconsin 17
Massachusetts 17
United States 17.2
Kansas 17.5
Minnesota 17.7
District of Columbia 18.2
Montana 18.9
North Dakota 19.2
Iowa 19.8
Hawaii 20.1
Texas 20.9
Georgia 21.1
New Mexico 21.5
Oklahoma 23.2
Alabama 23.7
North Carolina 25.3
Arkansas 26
South Dakota 26.2
Louisiana 28.4
Florida 29.3
South Carolina 30.9
Idaho 35.6
Mississippi 35.7